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[控制电缆] 控制电缆计算外径的问题
P:2009-03-18 17:11:05
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| 线芯排列 | K值 | ||||||
| 2芯 | 2 | 2 | 2 | ||||
| 3芯 | 3 | 3 | 2.154 | ||||
| 4芯 | 4 | 4 | 2.414 | ||||
| 5芯 | 5 | 5 | 2.7 | ||||
| 6芯 | 6 | 6 | 2.8 | ||||
| 7芯 | 1 | 6 | 7 | 3 | |||
| 8芯 | 1 | 7 | 8 | 3.3 (3.31) | |||
| 9芯 | 1 | 8 | 9 | 3.7 (3.62) | |||
| 10芯 | 2 | 8 | 10 | 4 (3.93) | |||
| 11芯 | 3 | 8 | 11 | 4.154(4) | |||
| 12芯 | 3 | 9 | 12 | 4.154 | |||
| 13芯 | 4 | 9 | 13 | 4.414(4.24) | |||
| 14芯 | 4 | 10 | 14 | 4.414 | |||
| 15芯 | 5 | 10 | 15 | 4.7(4.55) | |||
| 16芯 | 5 | 11 | 16 | 4.7 | |||
| 17芯 | 0 | 6 | 11 | 17 | 5 (4.86) | ||
| 18芯 | 0 | 6 | 12 | 18 | 5 | ||
| 19芯 | 1 | 6 | 12 | 19 | 5 | ||
| 20芯 | 1 | 6 | 13 | 20 | 5.154 | ||
| 21芯 | 1 | 7 | 13 | 21 | 5.3 | ||
| 22芯 | 1 | 8 | 13 | 22 | 5.7 | ||
| 23芯 | 2 | 8 | 13 | 23 | 6 | ||
| 24芯 | 2 | 8 | 14 | 24 | 6 | ||
这是一张成缆外径系数表。
例:KVV3*1.5成品外径计算:绝缘线芯直径如2.8mm;3芯成缆系数为:2.154;绝缘厚度=1.2mm
成缆外径=2.8*2.154=6.03
成品外径=6.03+(2*1.2)=8.43
compensating lead - 补偿线,补偿导线 （0） 投诉
P:2009-09-14 20:28:58
7
GB/T20637.2-2006附录成C中规定了电缆平均外径的上限和下限，电缆外径公式计算是:
最小外径：IF(0.97*AA5<=5,ROUND(0.97*AA5,1),IF(AND(0.97*AA5>5,0.97*AA5<=10),FLOOR(0.97*AA5,0.2),IF(0.97*AA5>10,FLOOR(0.97*AA5,0.5))))
最大外径：IF(1.05*AB5+0.4<=5,CEILING(1.05*AB5+0.4,0.1),IF(AND(1.05*AB5+0.5>5,1.05*AB5+0.5<=10),CEILING(1.05*AB5+0.5,0.2),IF(1.05*AB5+0.5>10,CEILING(1.05*AB5+0.5,0.5))))
phase-margin - 相位余量 （0） 投诉
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