电线电缆网 > 国外线缆 > 电线所能承载电流的计算公式（完整版）
电线所能承载电流的计算公式 - 无图版
droganwang --- 2011-02-21 16:49:13
1
做电线很多年，但对多大的电线能承载多大的电流还是没有一个清晰的认识和计算方法，请教行业高手。
droganwang --- 2011-02-22 10:55:27
2
有没有哪位高手知道指教下啊，，，刚有在网上查看，，，结果是五花八门的，，，像0.75MM2，有的说是3.75A，有的说是8A等等，，，，有没有计算公式的？
gebenhagen --- 2011-02-22 14:16:15
3
如何计算导体载流量
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| 计算导体载流量 | ||||||
| 绝缘铜导体25度时计算载流量A“铜线升级算” | ||||||
| 截面mm² | 倍数 | 计算载流量 | 导体穿管 | 计算载流量 | 温度大于25度时 | 计算载流量 |
| 1.5 | 5 | A=5*2.5 | 穿管打八折即乘0.8 | A=5*2.5*0.8 | 计算时打九折即乘0.9 | A=5*2.5*0.8*0.9 |
| 2.5 | A=5*4 | A=5*4*0.8 | A=5*4*0.8*0.9 | |||
| 4 | A=5*6 | A=5*6*0.8 | A=5*6*0.8*0.9 | |||
| 6 | A=5*10 | A=5*10*0.8 | A=5*10*0.8*0.9 | |||
| 10 | A=5*16 | A=5*16*0.8 | A=5*16*0.8*0.9 | |||
| 16 | 4 | A=4*25 | A=4*25*0.8 | A=4*25*0.8*0.9 | ||
| 25 | A=4*35 | A=4*35*0.8 | A=4*35*0.8*0.9 | |||
| 35 | 3 | A=3*50 | A=3*50*0.8 | A=3*50*0.8*0.9 | ||
| 50 | A=3*70 | A=3*70*0.8 | A=3*70*0.8*0.9 | |||
| 70 | 2.5 | A=2.5*95 | A=2.5*95*0.8 | A=2.5*95*0.8*0.9 | ||
| 95 | A=2.5*120 | A=2.5*120*0.8 | A=2.5*120*0.8*0.9 | |||
| 120 | 2 | A=2*150 | A=2*150*0.8 | A=2*150*0.8*0.9 | ||
| 150 | ||||||
| 185 | ||||||
| 240 | 1.6 | |||||
droganwang --- 2011-02-23 08:08:17
4
这些是电工手册里的吧，，，有没有计算公式呢，，，并且网上看的，都有些不一样，也不知哪个对？
gebenhagen --- 2011-02-23 12:43:51
5
电缆的载流量与铺设条件电缆结构及芯数有关，所以不同条件不同芯数不同结构的电缆载流量不同。
hanhezhang --- 2011-03-01 11:20:52
6
这个东西没有十分精确的
ly --- 2011-03-01 18:56:06
7
这也需要这个？有哪位大吓有没有更详细的计算方法？
droganwang --- 2011-03-03 11:30:36
8
是啊，各个版本都不一样，也不知哪个是对的？