电线电缆网 > 电力电缆 > 求高手指导载流量问题(完整版)
求高手指导载流量问题 - 无图版
jiabinghui --- 2012-05-04 08:55:53
1
请问哪位高手知道:YJLQ02-Z和YJLQ02 都是64/110kV 1×800mm2的电缆,其在土壤中都是等边三角形敷设,土壤系数1.0 这两个的规格的电缆载流量一样吗?都是多少呀?数据相当重要撒..........请高手指导!谢谢
2008ls --- 2012-05-04 10:48:01
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等待高手解惑!
500kV110 --- 2012-05-04 14:19:31
3
直接埋地平行敷设: | ||||
I={[(90-30)-0.295×(0.5×0.486+0.182+1.248)] | ||||
/[0.00002876×(0.486+(1+0.08)×(0.182+1.248))]}^0.5 | = | 1010 | (A) | |
直接埋地三角形敷设: | ||||
I={[(90-30)-0.295×(0.5×0.486+0.182+1.234)] | ||||
/[0.00002876×(0.486+(1+0.04)×(0.182+1.234))]}^0.5 | = | 1014 | (A) | |
穿管埋地平行敷设: | ||||
I={[(90-30)-0.295×(0.5×0.486+0.182+1.587)] | ||||
/[0.00002876×(0.486+(1+0.08)×(0.182+1.587))]}^0.5 | = | 929 | (A) | |
穿管埋地三角形敷设: | ||||
I={[(90-30)-0.295×(0.5×0.486+0.182+1.573)] | ||||
/[0.00002876×(0.486+(1+0.04)×(0.182+1.573))]}^0.5 | = | 932 | (A) | |
空气中平行敷设: | ||||
I={[(90-40)-0.295×(0.5×0.486+0.182+0.322)] | ||||
/[0.00002876×(0.486+(1+0.08)×(0.182+0.322))]}^0.5 | = | 1296 | (A) | |
空气中三角形敷设: | ||||
I={[(90-40)-0.295×(0.5×0.486+0.182+0.323)] | ||||
/[0.00002876×(0.486+(1+0.04)×(0.182+0.323))]}^0.5 | = | 1296 | (A) | |
穿管空气中平行敷设: | ||||
I={[(90-40)-0.295×(0.5×0.486+0.182+0.637)] | ||||
/[0.00002876×(0.486+(1+0.08)×(0.182+0.637))]}^0.5 | = | 1123 | (A) | |
穿管空气中三角形敷设: | ||||
I={[(90-40)-0.295×(0.5×0.486+0.182+0.638)] | ||||
/[0.00002876×(0.486+(1+0.04)×(0.182+0.638))]}^0.5 | = | 1122 | (A) |
500kV110 --- 2012-05-04 14:28:34
4
以上计算时,土壤系数1.0 ,空气温度40度,土壤温度30度。
[500kV110 在 2012-5-4 14:30:31 编辑过]
jiabinghui --- 2012-05-04 18:16:54
5
谢谢啦